(E)-3-Bromo-N′-(4-methoxybenzylidene)benzohydrazide methanol solvate

The title compound, C15H13BrN2O2·CH3OH, was synthesized by the reaction of 4-methoxybenzaldehyde with an equimolar quantity of 3-bromobenzohydrazide in methanol. The benzohydrazide molecule displays an E configuration about the C=N bond. The dihedral angle between the two benzene rings is 4.0 (2)°. The benzohydrazide and methanol molecules are linked into a chain propagating along the b axis by O—H...O, O—H...N, N—H...O and C—H...O hydrogen bonds.