%0 Journal Article
%T 整函数差分唯一性<br>Uniqueness of Difference about Entire Functions
%A 黄小皇
%A 刘丹
%J Pure Mathematics
%P 370-376
%@ 2160-7605
%D 2019
%I Hans Publishing
%R 10.12677/PM.2019.93049
%X <div style=\"text-align:justify;\">
	本文探讨整函数的差分唯一性问题，证明了：设f(z)为开平面有穷级整函数，g（z）=m<sub>i</sub>（z）f（z+c<sub>i</sub>）+…+m<sub>k</sub>（z）f（z+c<subk< sub=\"\">）</subk<>为f(z)的差分多项式，其中m<sub>i</sub>（z）（i=1，2，…，k）为f的整小函数， c<sub>i</sub>（i=1，2，…，k）k个判别的有穷复数。又设a(z)？0为f(z)的一个小函数，若f(z)与g(z)分担0，IM分担a(z) ，则f(z)=g(z) 。
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	&lt;br/&gt;In this paper, we investigate the uniqueness of difference operators about entire function, and prove: let <span>f(z)</span> be an entire function of finite order, k be some positive integers, let <span>a(z)</span> be a small function of <span>f(z)</span> , and let&nbsp;g（z）=m<sub>i</sub>（z）f（z+c<sub>i</sub>）+…+m<sub>k</sub>（z）f（z+c<subk< sub=\"\">）&nbsp;be the difference poly-nomial of <span>f(z)</span> , where&nbsp;m<sub>i</sub>（z）（i=1，2，…，k） &nbsp;are the small functions of <span>f(z)</span> , and&nbsp;c<sub>i</sub>（i=1，2，…，k） &nbsp;are some finite distinct values. If <span>f(z)</span> and <span>g(z)</span> share 0 CM, and share <span>a(z)</span>IM, then <span>f(z)=g<span>(z)</span></span> .</subk<>
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%K 整函数，分担小函数，差分多项式<br>Entire Function
%K Shared Small Function
%K Difference Polynomials
%U http://www.hanspub.org/journal/PaperInformation.aspx?PaperID=30322