%0 Journal Article
%T A New Method of Time Domain Solution and Stability Analysis for Periodic Orbits of Piecewise Linear Dynamic Systems
分段线性动态系统周期轨道的时域法求解及其稳定性分析
%A Hu Qing-bin
%A Lu Yuan-yuan
%A
胡庆彬
%A 卢元元
%J 电子与信息学报
%D 2008
%I
%X This paper proposes a new method to get time solutions of periodic orbits and to determine their stability for piecewise linear dynamic systems. The state space of piecewise linear dynamic system is cut into some linear subspaces by several switching surfaces. By solving together all the equations of periodic orbit in these subspaces with MATLAB, the coordinates of periodic orbit on each switching surface and the running time on each subspace are obtained, from which the time expressions in sections of periodic orbit can be derived. Based on these expressions, the Poincare mapping equation and the Jacobian matrix of periodic orbits can be deduced. According to the eigenvalues of the Jacobian matrix, the stability of the periodic orbit can be determined. Using 3rd-order and 4th-order Chau’s circuits as examples, the time expressions of many periodic orbits are obtained and their stability is determined respectively by the new method. The results are exact the same as that of digital simulations, which shows the new method is correct and practical.
%K Piecewise linear dynamic system
%K Periodic orbit
%K Stability
%K Time domain method
%K Poincare mapping
分段线性动态系统
%K 周期轨道
%K 稳定性
%K 时域法
%K 庞加莱映射
%K 分段
%K 线性动态系统
%K 周期轨道
%K 时域法
%K 联合求解
%K 稳定性判断
%K 分析
%K Dynamic
%K Systems
%K Piecewise
%K Linear
%K Periodic
%K Orbits
%K Stability
%K Analysis
%K Solution
%K Time
%K Domain
%K 数字仿真
%K 蔡氏电路
%K 四阶
%K 特征值
%K 雅可比矩阵
%K 映射方程
%K 庞加莱
%U http://www.alljournals.cn/get_abstract_url.aspx?pcid=5B3AB970F71A803DEACDC0559115BFCF0A068CD97DD29835&cid=1319827C0C74AAE8D654BEA21B7F54D3&jid=EFC0377B03BD8D0EF4BBB548AC5F739A&aid=A2CDEBCB9B796D79C256A0D94E26D590&yid=67289AFF6305E306&vid=340AC2BF8E7AB4FD&iid=CA4FD0336C81A37A&sid=6700D0D256586E73&eid=A4FA325EA800C820&journal_id=1009-5896&journal_name=电子与信息学报&referenced_num=0&reference_num=9